Microlocal analysis of the HUM operator for a system of wave
Transcription
Microlocal analysis of the HUM operator for a system of wave
Microlocal analysis of the HUM operator for a system of wave equations Jérôme Le Rousseau Université d’Orléans – Fédération Denis-Poisson A joint work with Belhassen Dehman (Faculté des Sciences de Tunis) and Matthieu Léautaud (Université Paris 7) Laboratoire Jacques-Louis Lions Université Pierre-et-Marie-Curie, October 2012 1/ 36 J. Le Rousseau coupled wave equations Setting Let Ω be a Riemannian compact manifold Ω (without boundary) ∆ is the Laplace-Beltrami operator on Ω We consider the following system 2 in (0, T ) × Ω, ∂t u1 − ∆u1 + bu2 = 0 ∂t2 u2 − ∆u2 = χg in (0, T ) × Ω, (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (u01 , u11 , u02 , u12 ) in Ω. χ ∈ C ∞ (Ω) and ω = {χ 6= 0}. We wish to bring the solutions at rest at times t ≥ T : (u1 , ∂t u1 , u2 , ∂t u2 )|t=T = (0, 0, 0, 0). The system has a cascade structure. The control g only acts on one of the equations. The second equation can only be controlled through the coupling term bu2 2/ 36 J. Le Rousseau coupled wave equations Setting Let Ω be a Riemannian compact manifold Ω (without boundary) ∆ is the Laplace-Beltrami operator on Ω Equivalently we consider the following system 2 in (0, T ) × Ω, ∂t u1 − ∆u1 + bu2 = 0 ∂t2 u2 − ∆u2 = χg in (0, T ) × Ω, (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (0, 0, 0, 0) in Ω. χ ∈ C ∞ (Ω) and ω = {χ 6= 0}. We wish to bring the solutions at time t ≥ T to a prescribed state: (u1 , ∂t u1 , u2 , ∂t u2 )|t=T = (u01 , u11 , u02 , u12 ). 3/ 36 J. Le Rousseau coupled wave equations Setting We consider the following system 2 in (0, T ) × Ω, ∂t u1 − ∆u1 + bu2 = 0 ∂t2 u2 − ∆u2 = χg in (0, T ) × Ω, (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (0, 0, 0, 0) in Ω. We wish to bring the solutions at time t ≥ T to : (u1 , ∂t u1 , u2 , ∂t u2 )|t=T = (u01 , u11 , u02 , u12 ). Regularity Issue g ∈ L2 ((0, T ) × Ω), =⇒ (u2 , ∂t u2 ) ∈ C 0 [0, T ], H01 × L2 =⇒ (u1 , ∂t u1 ) ∈ C 0 [0, T ], (H 2 ∩ H01 ) × H01 we therefore need (u1 , ∂t u1 , u2 , ∂t u2 )|t=T ∈ (H 2 ∩ H01 ) × H01 × H01 × L2 This is the natural space for the analysis of the control problem. First results known for weak constant coupling (symmetric system) in [Alabau-Boussouira: 03] 4/ 36 J. Le Rousseau coupled wave equations Setting Alternative formulation 1 ∂t2 u1 − ∆u1 + b(1 − ∆) 2 u2 = 0 ∂ 2 u − ∆u2 = χg t 2 (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (0, 0, 0, 0) in (0, T ) × Ω, in (0, T ) × Ω, in Ω. Regularity g ∈ L2 ((0, T ) × Ω), =⇒ (u1 , ∂t u1 ) ∈ C 0 [0, T ], H01 × L2 =⇒ (u2 , ∂t u2 ) ∈ C 0 [0, T ], H01 × L2 We therefore need (u1 , ∂t u1 , u2 , ∂t u2 )|t=T ∈ H01 × L2 × H01 × L2 5/ 36 J. Le Rousseau coupled wave equations Setting 1 ∂t2 u1 − ∆u1 + b(1 − ∆) 2 u2 = 0 ∂ 2 u − ∆u2 = χg t 2 (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (0, 0, 0, 0) in (0, T ) × Ω, in (0, T ) × Ω, in Ω. Control space g ∈ L2 ((0, T ) × Ω) → state space (u1 , ∂t u1 , u2 , ∂t u2 ) ∈ H01 × L2 × H01 × L2 . We also need conditions on both the supports of the control function and the coupling term; the time T . 6/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation I Consider the control problem 2 in ∂t u − ∆u = χg u=0 on (u(0), ∂t u(0)) = (0, 0) (0, T ) × Ω (0, T ) × ×∂Ω Wave symbol: p = −τ 2 + R(x, ξ) (flat case: R(x, ξ) = |ξ|2 , here R(x, ξ) = |ξ|2x ) Hamiltonian vector field: Hp = (∂τ p)∂t − (∂t p)∂τ + (∂ξ p)∂x − (∂x p)∂ξ Integral curves for Hp dx dt = ∂τ p(t, x, τ, ξ) = ∂ξ p(t, x, τ, ξ) ds ds dτ dξ = −∂t p(t, x, τ, ξ) = 0 = −∂x p(t, x, τ, ξ) ds ds Rays or bicharacteristics: integral curves for Hp within the characteristic set p = 0. Singularities travel along such bicharacteristics (Hörmander) 7/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation I Geometric control condition [Rauch-Taylor ’74, Bardos-Lebeau-Rauch ’92] Case of manifold without boundary. (ω, T ) is said to satisfy GCC at time T if all bicharacteristics starting from (x, ξ) at time t = 0 enter ω = {χ 6= 0} before t = T . Case of manifold with boundary. (ω, T ) is said to satisfy GCC at time T if all generalized bicharacteristics starting from (x, ξ) at time t = 0 enter ω = {χ 6= 0} before t = T . Generalized bicharacteristics are described in [Melrose-Sjöstrand ’78, ’82] Theorem (Bardos-Lebeau-Rauch ’92, Burq-Gérard’ 97) GCC is equivalent to the exact controllability of the wave equation at time T 8/ 36 J. Le Rousseau coupled wave equations Back to the system of two wave equations... The system is 1 ∂t2 u1 − ∆u1 + b(1 − ∆) 2 u2 = 0 ∂ 2 u − ∆u2 = χg t 2 (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (0, 0, 0, 0) in (0, T ) × Ω, in (0, T ) × Ω, in Ω. with b ≥ 0. ω = {χ 6= 0}, O = {b > 0} Necessary condition to controllability (ω, Tω ) satisfies GCC (O, TO ) satisfies GCC Definition Given two sets ω and O both satisfying GCC, we set Tω→O→ω the infimum of times T > 0 s.t. every bicharacteristics traveling at speed one in Ω meets ω in a time t0 < T , meets O in a time t1 ∈ (t0 , T ) and meets ω again in a time t2 ∈ (t1 , T ). Observe that max TO , Tω ≤ Tω→O→ω ≤ 2Tω + TO . J. Le Rousseau coupled wave equations 9/ 36 System of two wave equations T Tω→O→ω t2 t1 t0 t=0 O ω Ω Figure: Geometric condition and time Tω→O→ω . 10/ 36 J. Le Rousseau coupled wave equations System of two wave equations O ω O ω Figure: Examples of open sets (Ω, ω, O) s.t. ω and O both satisfy GCC in Ω: case (a), Ω is the flat torus (or the square), case (b), Ω is the disk. 11/ 36 J. Le Rousseau coupled wave equations System of two wave equations 1 ∂t2 u1 − ∆u1 + b(1 − ∆) 2 u2 = 0 ∂ 2 u − ∆u2 = χg t 2 (u1 , ∂t u1 , u2 , ∂t u2 )|t=0 = (0, 0, 0, 0) with b ≥ 0. in (0, T ) × Ω, in (0, T ) × Ω, in Ω. Theorem (Dehman, LR, Léautaud) Let Ω be a compact manifold without boundary. If ω = {χ 6= 0} satisfies GCC O = {b > 0} satisfies GCC T > Tω→O→ω then the system is exactly controllable. If either ω does not satisfy GCC or O does not satisfy GCC or T < Tω→O→ω the system is NOT controllable. J. Le Rousseau 12/ 36 coupled wave equations System of two wave equations Existing results [F. Alabau-Boussouira - M. Leautaud ’11] symmetric systems, weak coupling, long control time. [L. Rosier - L. de Teresa ’11] 1-D, geometric but not sharp control time. [F. Alabau-Boussouira] Cascade of N equations, long control time. 13/ 36 J. Le Rousseau coupled wave equations System of two wave equations Adjoint system: 2 (∂t − ∆)w1 = 0 1 (∂t2 − ∆)w2 = −b(x)(1 − ∆) 2 w1 in (0, T ) × Ω in (0, T ) × Ω. (Adj) Controllability is equivalent to the observability inequality: T e0 (w1 (0)) + e0 (w2 (0)) ≤ C ∫ ∫ |χw2 |2 dx dt, (Obs) 0Ω for all (w1 , w2 ) solutions of (Adj). Here e0 (w) = kwk2L2 (Ω) + k∂t wk2H −1 (Ω) . 14/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II Adjoint equation for the wave equation: (∂t2 − ∆)v = 0 in (0, T ) × Ω We set V = (v, ∂t v) Controllability is equivalent to the observability inequality: T e0 (V (0)) ≤ C ∫ ∫ |χv|2 dx dt, 0Ω for all v solution of the adjoint equation. Here e0 (V (0)) = kv(0)k2L2 (Ω) + k∂t v(0)k2H −1 (Ω) 15/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II Controlled equation: (∂t2 − ∆)u = χg U (t) = (u(t), ∂t u(t)) ∈ H 1 (Ω) × L2 (Ω). Adjoint equation: (∂t2 − ∆)v = 0 in (0, T ) × Ω in (0, T ) × Ω. With an integration by parts we have: =0 hχg, viL2 ((0,T )×Ω) = h∂t u(T ), v(T )iL2 z }| { − h∂t u(0), v(0)iL2 − hu(T ), ∂t v(T )iH 1 ,H −1 − hu(0), ∂t v(0)iH 1 ,H −1 | {z } =0 We introduce the maps L : L2 (Ω) × H −1 (Ω) → L2 ((0, T ) × Ω) VT = V (T ) = (v(T ), ∂t v(T )) 7→ χv and M : L2 ((0, T ) × Ω) → H 1 (Ω) × L2 (Ω) g 7→ (−u(T ), ∂t u(T )) 16/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II In the HUM approach we seek the control as a solution of the backward wave equation: we set g = L(VT ) = χv. Then (u(T ), ∂t u(T )) = M ◦ L(VT ) We then find kL(VT )k2L2 ((0,T )×Ω) = h∂t u(T ), v(T )iL2 − hu(T ), ∂t v(T )iH 1 ,H −1 = hU (T ), VT i∗ = hM ◦ L(VT ), VT i∗ where hU, V i∗ = hU2 , V1 iL2 +hU1 , V2 iH 1 ,H −1 , U ∈ H 1 ×L2 , V ∈ L2 ×H −1 G = M ◦ L is the Gramian operator. 17/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II We have kL(VT )k2L2 ((0,T )×Ω) = hG (VT ), VT i∗ Note that G : L2 (Ω) × H −1 (Ω) → H 1 (Ω) × L2 (Ω) 18/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II We have kL(VT )k2L2 ((0,T )×Ω) = hG (VT ), VT i∗ Note that G : L2 (Ω) × H −1 (Ω) → H 1 (Ω) × L2 (Ω) Observability: kVT kL2 ×H −1 ≤ CkL(VT )kL2 ((0,T )×Ω) We have controllability ⇔ observability ⇔ invertibility of G 18/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II We have kL(VT )k2L2 ((0,T )×Ω) = hG (VT ), VT i∗ Note that G : L2 (Ω) × H −1 (Ω) → H 1 (Ω) × L2 (Ω) Observability: kVT kL2 ×H −1 ≤ CkL(VT )kL2 ((0,T )×Ω) We have controllability ⇔ observability ⇔ invertibility of G In such case we can solve G (VT ) = UT with UT = (−u0 , u1 ) ∈ H 1 × L2 The HUM operator is precisely G −1 18/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II We have kL(VT )k2L2 ((0,T )×Ω) = hG (VT ), VT i∗ Note that G : L2 (Ω) × H −1 (Ω) → H 1 (Ω) × L2 (Ω) Observability: kVT kL2 ×H −1 ≤ CkL(VT )kL2 ((0,T )×Ω) We have ⇔ observability ⇔ invertibility of G controllability In such case we can solve G (VT ) = UT with UT = (−u0 , u1 ) ∈ H 1 × L2 The HUM operator is precisely G −1 The controlled equation is then (∂t2 − ∆)u = χL(VT ) in (0, T ) × Ω (u(0), ∂t u(0)) = (0, 0) and we obtain (u(T ), ∂t u(T )) = (u0 , u1 ). 18/ 36 J. Le Rousseau coupled wave equations Review of the controllability of the wave equation II We have kL(VT )k2L2 ((0,T )×Ω) = hG (VT ), VT i∗ Note that G : L2 (Ω) × H −1 (Ω) → H 1 (Ω) × L2 (Ω) Observability: kVT kL2 ×H −1 ≤ CkL(VT )kL2 ((0,T )×Ω) We have ⇔ observability ⇔ invertibility of G controllability In such case we can solve G (VT ) = UT with UT = (−u0 , u1 ) ∈ H 1 × L2 The HUM operator is precisely G −1 The controlled equation is then (∂t2 − ∆)u = χL(VT ) in (0, T ) × Ω (u(0), ∂t u(0)) = (0, 0) and we obtain (u(T ), ∂t u(T )) = (u0 , u1 ). Question: can we prove directly the invertibility of the Gramian operator G ? 18/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian In part we follow the approach of Dehman-Lebeau Here, to expose their method, we consider a simplified model to avoid technicalities We consider the half-wave first-order equation √ ∂t u − iλu = χg ∈ L2 (Ω), λ = −∆, u(0) = 0 λ is pseudo-differential of order 1 with principal symbol |ξ| We have u ∈ C 0 ([0, T ]; L2 (Ω)) ∩ C 1 ([0, T ]; H −1 (Ω)) Note that (∂t − iλ)(∂t + iλ) = ∂t2 − ∆. We have factorized the wave equation The adjoint equation is ∂t v − iλv = 0 ∈ L2 (Ω), v(T ) = vT 19/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian ∂t u − iλu = χg ∈ L2 (Ω), u(0) = 0 The adjoint equation is ∂t v − iλv = 0 ∈ L2 (Ω), v(T ) = vT Proceeding as above we find hχg, viL2 ((0,T )×Ω) = hu(T ), v(T )iL2 . We introduce the maps L : L2 (Ω) → L2 ((0, T ) × Ω) vT = v(T ) 7→ χv and M : L2 ((0, T ) × Ω) → L2 (Ω) g 7→ u(T ) and set G = M ◦ L. 20/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian ∂t u − iλu = χg ∈ L2 (Ω), u(0) = 0 The adjoint equation is ∂t v − iλv = 0 ∈ L2 (Ω), v(T ) = vT Setting g = L(vT ) we have kL(vT )k2L2 ((0,T )×Ω) = hG vT , vT iL2 . controllability ⇔ observability ⇔ invertibility of G 21/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian ∂t u − iλu = χg ∈ L2 (Ω), u(0) = 0 Changing t → T − t in the adjoint equation ∂t v + iλv = 0 ∈ L2 (Ω), v(0) = v0 We have kL(v0 )k2L2 ((0,T )×Ω) = hG v0 , v0 iL2 . controllability ⇔ observability ⇔ invertibility of G 22/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian Bicharacterisitic flow: we introduce ϕ solution to d ± ϕs (x, ξ) = H∓|ξ|x ϕs (x, ξ) , ds ∗ ϕ± 0 (x, ξ) = (x, ξ) ∈ T Ω \ 0. N.B. H∓|ξ|x is the vector field: ∓(∂ξ |ξ|x )∂x ± (∂x |ξ|x )∂ξ . 23/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian The adjoint equation is ∂t v + iλv = 0 ∈ L2 (Ω), λ= √ −∆, v(0) = v0 The gives v(0) = e−itλ v0 (Fourier integral operator) N.B. Here we ignore the eigenvalue 0 Then we compute the observation T T 0 0 ∫ kχvk2L2 (Ω) dt = ∫ heitλ χ2 e−itλ v0 , v0 iL2 (Ω) dt We thus have G v0 = ∫0T eitλ χ2 e−itλ v0 dt. By the Egorov theorem eitλ χ2 e−itλ is a pseudo-differential operator of order 0 with principal symbol σ(t, x, ξ) = χ2 ◦ ϕ− t (x, ξ) The Gramian is thus a pseudo-differential operator of order 0 with symbol T ∫ χ2 ◦ ϕ− t (x, ξ) dt 0 24/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian The Gramian is thus a pseudo-differential operator of order 0 with symbol T ∫ χ2 ◦ ϕ− t (x, ξ) dt 0 For the Gramian to be invertible one needs it to be elliptic, that is (order 0) T ∫ χ2 ◦ ϕ− t (x, ξ) dt ≥ C, ∀(x, ξ) ∈ T ∗ (Ω) 0 We thus recover the GC condition of Bardos-Lebeau-Rauch. 25/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian Theorem (Dehman-Lebeau) We have {χ > 0} satisfies GCC ⇔ the operator G is elliptic. Moreover in such case 1 2 the operator G is coercive and invertible; the HUM operator G −1 can be written as G −1 = Λ + R when R is a regularizing operator and Λ is a pseudo-differential operator of order 0 with principal symbol T −1 ∫ χ2 ◦ ϕ− (x, ξ) dt t 0 26/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian The proof of coercivity goes along two steps with a compactness-uniqueness argument as in the original proof of Bardos-Lebeau-Rauch for the controllability of the wave equation. We acknowledge very fruitful discussions with C. Laurent on some aspects of the proof. 27/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian First-step: from the ellipticity of G we find with the Gårding inequality: hG v0 , v0 iL2 ≥ Ckv0 k2L2 − C 0 kv0 k2 − 1 . H 2 (1) We thus have coercivity for the high-frequencies. Second-step: We consider N (T ) = {v0 ∈ L2 (Ω); L(v) = χv(t, x) = 0 in (0, T ) × ω}, By proving that the unit sphere in N (T ) is compact from (1) we have Lemma The space N (T ) is finite dimensional. Moreover if v0 ∈ N (T ) then χv = 0, implying χ∂t v = 0. This implies Lv0 ∈ N (T ). 28/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian Second-step (continued): Hence, N (T ) is stable under λ and is finite dimensional. If N (T ) 6= {0}, this implies that there exist λ and w 6= 0, such that w ∈ N (T ), λw = λw, χw = 0, We thus have −∆w = λ2 w and χw = 0. A classical unique continuation result yields w = 0 Lemma We have N (T ) = {0}. 29/ 36 J. Le Rousseau coupled wave equations Analysis of the Gramian Second-step (continued): We assume that coercivity does not hold: (n) There exists (v0 ) ⊂ L2 (Ω) such that (n) kv0 k = 1 (n) We have v0 (n) kG v0 kL2 (Ω) → 0 * v ∈ L2 (Ω). Continuity of the half wave equation yields v ∈ N (T ), that is v = 0 (n) In particular we have v0 → 0 in H −1 (Ω). The high-frequency result: hG v0 , v0 iL2 ≥ Ckv0 k2L2 − C 0 kv0 k2 1 H− 2 then implies the contradiction 0 ≥ C − C 0 × 0. 30/ 36 J. Le Rousseau coupled wave equations Back to systems Again we√consider a simplified model here for the sake of exposition: Set λ = −∆ on L2+ , projecting onto the orthogonal of the space of constant functions. Consider: ( 1 bu2 = 0 in (0, T ) × Ω, (∂t − iλ)u1 − 2i (∂t − iλ)u2 = χf in (0, T ) × Ω. Adjoint system: (∂t + iλ)v1 = 0 1 (∂t + iλ)v2 + 2i bv1 = 0 (v1 (0), v2 (0)) = (g, h) ∈ L2 (Ω; C2 ) in (0, T ) × Ω, in (0, T ) × Ω, The observability inequality reads T kgk2L2 (Ω) + khk2L2 (Ω) ≤ C ∫ kχv2 k2L2 (Ω) dt. 0 31/ 36 J. Le Rousseau coupled wave equations Microlocal characterization of the HUM operator The Gramian operator is given by T ∫ kχv2 k2L2 (Ω) dt = G (g, h), (g, h) 0 L2 (Ω;C2 ) . If the wave system is exactly controllable then G is invertible and the HUM operator is G −1 Theorem There exists G ∈ Ψ0 (Ω; C2×2 ), and R an infinitely smoothing operator on Ω such that G = G + R, where the principal symbol (in S 0 (T ∗ Ω, C2×2 )) of G is 2 t t − − 1 T 2 1 T 2 − − dt dt χ ◦ ϕ ∫ b ◦ ϕ dσ χ ◦ ϕ ∫ b ◦ ϕ dσ ∫ ∫ t t σ 0 σ 2i 0 4 0 0 1 T 2 − 2i ∫0T χ2 ◦ ϕ− ∫0 χ ◦ ϕ− ∫0t b ◦ ϕ− t dt t σ dσ dt 32/ 36 J. Le Rousseau coupled wave equations Microlocal characterization of the HUM operator Theorem (continued) In particular, we have det(σ0 (G)) = t2 2 1TT 2 − − ∫ ∫ (χ ◦ϕt1 )(χ2 ◦ϕ− dt1 dt2 ∈ S 0 (T ∗ Ω). t2 ) ∫ b◦ϕσ dσ 800 t1 The operator G is coercive on L2 (Ω; C2 ). The operator G is invertible in L(L2 (Ω)). Its inverse (G )−1 , the HUM operator, can be decomposed as (G )−1 = Λ + R where R is smoothing and Λ ∈ Ψ0 (T ∗ Ω, C2×2 ), with principal symbol det(σ0 (G))−1 ∫0T χ2 ◦ ϕt dt × 1 T 2 − 2i ∫0 χ ◦ ϕ− ∫0t b ◦ ϕ− t σ dσ dt ∫0T χ2 ◦ ϕ− ∫0t b ◦ ϕ− t σ dσ dt 2 t − 1 T 2 − ∫ χ ◦ ϕ ∫ b ◦ ϕ dσ dt t 0 σ 0 4 1 2i 33/ 36 J. Le Rousseau coupled wave equations Microlocal characterization of the HUM operator det(σ0 (G)) = t2 2 1TT 2 − 2 − ∫ ∫ (χ ◦ ϕ− dt0 dt2 ∈ S 0 (T ∗ Ω). t0 )(χ ◦ ϕt2 ) ∫ b ◦ ϕσ dσ 800 t0 T Tω→O→ω t2 φt1 (B) t∗ ρ∗ t1 t0 φt0 (B) B O ω Ω Observe that the geometric condition appears clearly in det(σ0 (G)). J. Le Rousseau coupled wave equations 34/ 36 Microlocal characterization of the HUM operator Sketch of proof. The Duhamel formula gives v1 (t) = e−itλ g, v2 (t) = e−itλ h − 1 t −i(t−σ)λ ∫e bv1 (σ)dσ. 2i 0 We compute T ∫ kχv2 k2L2 (Ω) dt = (G + R)(g, h), (g, h) )L2 0 with G= 1 4 1 T ∫0T (Bt )∗ eitλ χ2 e−itλ Bt dt + 2i ∫0 (Bt )∗ eitλ χ2 e−itλ dt 1 T itλ 2 −itλ Bt dt ∫0T eitλ χ2 e−itλ dt − 2i ∫0 e χ e , where t Bt := ∫ eiσλ be−iσλ dσ 0 The conclusion follows from the Egorov Theorem. 35/ 36 J. Le Rousseau coupled wave equations Thank you for your attention. Further details in: B. Dehman, J. Le Rousseau, and M. Léautaud. Controllability of two coupled wave equations on a compact manifold, preprint 2012, 53 pages. http://hal.archives-ouvertes.fr/hal-00686967 36/ 36 J. Le Rousseau coupled wave equations