Definite Integration with u-Substitution - Homework
Transcription
Definite Integration with u-Substitution - Homework
Definite Integration with u-Substitution - Homework S)*>!(42!;7&'2+!%9!(42!9%&&%3)*6!>29)*)(2!)*(2657&+0!k25)9Q!'+)*6!Q%'5!=7&='&7(%50!$%?2!3)&&!'+2!0,+':+()('()%*X %(425+!3)&&!*%(0 ! "x -0! %3 4 2 # 1# dx 3 /0! ! x" #2 # x # 1 dx 0 % 4 'x4 * ) # x, !!! ( 4 +#2 1 !!!!!!! 2 24 64 #8#0 ! 5 5 4 # 2 # " 4 ( 2# ! #4 % 12 1 ! "1 # cos 2 x # dx .0! ! 2 x" x 2 3 ! 2 sin 2 x dx u ! 2 x, du ! 2 dx 0 2% 3 ! sin u du 1 # 2 % 12 x0 2% 3 1 1 1 3 "# cos u# 0 ! ( ! 2 4 2 4 3 2 ( 1# dx E0! % 1 # 12 2 2 | u ! 2 x, du ! 2 x dx 1 ! 2 x" x 0 %6 ! cos u du 2 2 2 ( 1# dx ! 0 | x ! 0, u ! 0 | x ! % 12 , u ! % 6 !! 12 #1 1 #2 x "9 # x 2 # dx ! 2 0 ! u du 2 0 !! x ! 0, u ! 9 | x ! 3, u ! 0 x ! 0, u ! 1 | x ! 1, u ! 2 0 9 2 - u3 0 8 1 7 / 2 ! # ! . 3 11 3 1 3 5 #1 0 1 2 1 - 2u3 2 0 ! u du ! 2 /. 3 21 ! 9 2 9 0 3 4 ! x # 4 dx G0! ! 0 x # x dx I0! 2 3 ! 5 ! "4 # x # dx ( ! " x # 4# dx !" 0 4 0 5 4 ' * x2* 'x2 )4 x # , ( ) # 4 x, 2 +0 ( 2 ( +4 25 17 16 # 8 ( # 20 # "8 # 16# ! 2 2 4 ! 0 ! 2"2t ( 1# 9 1 ! " x # x # dx 4 1 #1 2 #1 2 1 !!!!!!!!! 2 2 # 3# 1 2 t sin t dt u ! cos t, du ! # sin t dt 0 9 du ! " u1 2 # ! 3 # 1 # 2 1 dx ! dx 5 12 3 ! 2 x" x 2 #2 # 3# dx 2 6 6 #1 1 5 1 - #10 ! u du ! 2 /. u 21 ! 12 ( 2 ! 12 1 1 #2 %2 3 # ! # cos3 t sin t dt dt 2 2 x ! 2, u ! 1 | x ! 3, u ! 6 2 1 16 - 1 2 0 # ( 8 # #/ # 2 ! 3 3 2 3 . 2 31 ! cos " x 2 # 3# u ! x 2 # 3, du ! 2 x dx 1 '2 x 3 2 x 2 * ' x 2 2 x 3 2 * # , () # !!!!!!!!!! ) , 2 +0 ( 2 3 +1 ( 3 "x -/0!! 0 0 !u # %2 4 2 4 x # x dx ( --0! t ! 0, u ! 1 | t ! 4, u ! 9 1 2 1 x x %2 dt 2t ( 1 u ! 2 t ( 1, du ! 2 dt 1 2 ! 0 4 9 # x 2 dx u ! 9 # x 2 , du ! #2 x dx u ! x ( 1, du ! 2 x dx %6 % 1 % 1 # "sin u# 0 ! # 12 2 12 4 -D0! !x 0 % 12 ! 2 cos 2 x dx x ! % 3, u ! 2 % 3 x ! 0, u ! 0 0 0 0 F0! 1 2 '2 x 5 2 x 2 * # , ) 2 +0 ( 5 2 B0! ! sin"2 x # dx C0! 0 ! t sin"% # t # dt 2 0 2 u ! % # t , du ! #2 t dt 1 # 2 %2 ! 2t sin"% # t # dt 2 0 t ! 0, u ! 1 | t ! % 2 , u ! 0 !!!!! t ! 0, u ! % | t ! % 2 2 , u ! % 2 1 0 %2 - u4 0 1 3 %2 1 1 1 1 # ! u du ! / 2 ! # ! sin cos u du u ! "0 ( 1# ! " # ! % 4 4 . 1 1 2 2 % 2 2 0 !!!"#$%&'(#$&)#'*&+(",+- !! ! ! "#! $%&'()%*+!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!,!-.G!,!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!. /&0. /,)!$(&1 % 3 %4 -C0! ! 2 tan x sec x dx !!!!!!!!!!!!!!!!!!!! !-B0! 1 ! cos x 1 # cos2 x dx !!!!!!!!!! -.0! 0 0 !x ax 2 ( b dx 0 % 3 2 u ! ax ( b, du ! 2 ax dx ! cos x sin x dx 1 2a 0 1 ! 2ax ax 2 ( b dx u ! tan x, du ! sec x dx u ! sin x, du ! cos x dx 0 x ! 0, u ! 0 | x ! % 4 , u ! 1 !!!!!! !!! x ! 0, u ! b | x ! 1, u ! a ( b x ! 0, u ! 0 | x ! % 3, u ! 3 2 1 1 3 2 32 - 2u 0 a (b 3 2 2 3 2 ax 2 ( b# # b 3 2 - u2 0 - 1 0- 2 u 3 2 0 " 1 a (b 1 2 3 ! u1 2du ! /. 3 21 ! 3 ! u du ! /. 2a 21/. 3 21 ! ! u du ! /. 2 21 ! 8 0 0 2 3a a b 0 b 0 2 %2 4 sin x dx -E0! ! x %2 4 u ! x , du ! -F0! ! 9# x 4 2 dx -G0! 2 x 3 sin x dx 2 ! x 2 2 % 4 4 ! "9 # x 2 # dx ( ! "x 0 3 2 # 9# dx 3 3 4 !!!!!!!!!!!!! ' * x * 'x3 )9 x # , ( ) # 9 x, x ! % 2 4 , u ! % 2 | x ! % 2, u ! % 3 +0 ( 3 ( +3 % % 2 ! sin u du ! "#2 cos u# % 2 ! 2 27 # 9 ( %2 2 ! f " x # dx ! 0 -I0!! ! f " x # dx ! #2 2 M9! ! f " x # dx ! 0 /B0! ! #2 0 f " x # dx ! ! /D0!! f " x # dx ! #2 11 and 3 0 22 3 0 2 ! 3 f " x # dx ! 11 !!/C0! ! f "3x # dx ! 5 #2 0 0 2 ! 2 f " x # dx ! 0 #2 6 f " u# du ! /E0! ! # f " x # dx ! 0 1 3 #11 /F0! 3 0 ! 3 f "3x # dx 0 1 "15# ! 5 3 2 ! 3 f " x # dx ! #11 !/G0! ! f "3x # dx ! 0 #2 #2 2 /C0! x ! 0, u ! 0 | x ! 2, u ! 6 0 0 #11 //0! 3 ! f " x # dx ! 15, f " x # !)+!7*!%>>!9'*=()%*!<+Q??2(5)=!(%!(42!%5)6)*@X!9)*>!(42!9%&&%3)*6N u ! 3 x du ! 3dx ! 2 ! # f " x # dx ! /-0! 6 #11 !!/.0!! 3 1 3 64 64 # 36 # "9 # 27# ! 3 3 ! f " x # dx ! 15, f " x # !)+!7*!2;2*!9'*=()%*!<+Q??2(5)=!(%!(42!6!,!7R)+@X!9)*>!(42!9%&&%3)*6N 2 11 3 1 is not continuous at x ! 0, x2 !!!!! the definite integral which represents area under the curve makes no sense. Since 6 11 and 3 0 dx !<#2!=7529'&l@ 9 # x 2 ! 0 4 x ! )3 dx %2 M9! 2 #4 0 1 1 !x u ! 3 x du ! 3dx 1 2 ! 3 f "3x # dx 3 #2 /G0! x ! #2, u ! #6 | x ! 2, u ! 6 1 6 1 f " u# du ! "0# ! 0 ! 3 #6 3 !!!"#$%&'(#$&)#'*&+(",+- !! ! ! "#! $%&'()%*+!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!,!-.I!,!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!. /&0. /,)!$(&1