Cal I Review
Transcription
Cal I Review
Review of Cal I Trig Derivatives: d [sin u ] dx d [cos u ] dx d [tan u ] dx d [sec u ] dx d [cot u ] dx d [csc u ] dx Exponential and Natural Log Functions: f ( x) e x 2x d u du [e ] eu dx dx and f ( x) ln(sin( x)) d n [ x ] nx n 1 dx 4 3 f ( x) x 3x 6 x 2 x Power Rule: Product Rule: d [uv] uv vu dx f ( x) x3 cos x Quotient Rule: x3 1 f ( x) 2 x 2 d 1 du u ( x ) or [ln u ] dx u dx u d u vu uv d T BT TB OR 2 dx v v dx B B2 d u n nu n1u dx Chain Rule: f ( x) 3 x 2 5 x 1 4 f ( x) sin 3 (5 x) f ( x) tan 5 3x 2 1 Implicit Differentiation: dy , given x 3 4 x 2 y 4 3 y 5 9 Find dx dy , given cos( xy ) y 3 4 dx Find Integrals: f ( x)dx = a set of antiderivatives k du k u C sin(u ) du cos(u ) C cos(u ) du sin(u ) C sec (u ) du tan(u ) C 2 u u e du e C 1 3 3 x 3 x 5 dx x Why a set? Review of Basic Forms u n 1 n u du n 1 C n 1 csc(u ) cot(u ) du csc(u ) C sec(u ) tan(u ) du sec(u ) C csc (u ) du cot(u ) C 2 1 du ln u C u x(5x 2 4)3 dx 6x2 dx 3 5 (4 x 9) cos x dx 3 sin x x sin(6 x )dx tan x sec2 xdx x dx 2 x 1 2 x 2 xe dx 2 Review of Basic Integration Rules ReviewBasicInverseTrigDerivatives: d u d u (arcsin u ) (arctan u ) dx dx 1 u2 1 u2 d u (arccos u ) dx 1 u2 d (arcsec u ) dx u d (arccsc u ) dx u u d (arccot u ) dx 1 u2 Review Basic Inverse Trig Integration: du 2 a u2 du u u2 a2 du 2 a u2 Find the indefinite integral: 1 dx 2 2 9x 1 dx 2 x 4x 9 1 25 36 x 2 dx u u2 1 u u2 1 ImproperFractions: The degree of the numerator is greater than or equal to the degree of the denominator. You must DIVIDE to change to a "mixed" fraction before you integrate. x 1 dx 2 x 1 4 x dx 2 x 1 2 4x 7 dx 2x 3 2 1 (Hint: Remember du ln u C u SeparatingFractions: x x x x dx 2 dx 2 1 x 1 x 4 You CANNOT separate denominators. 2 8x dx 2 1 4x 4